Nuprl Lemma : derivative_functionality2

I,J:Interval.
  ∀[f1,f2,g1,g2:I ⟶ℝ].
    (rfun-eq(I;f1;f2)  rfun-eq(I;g1;g2)  J ⊆ I   d(f1[x])/dx = λx.g1[x] on  d(f2[x])/dx = λx.g2[x] on J)


Proof




Definitions occuring in Statement :  derivative: d(f[x])/dx = λz.g[z] on I subinterval: I ⊆  rfun-eq: rfun-eq(I;f;g) rfun: I ⟶ℝ interval: Interval uall: [x:A]. B[x] so_apply: x[s] all: x:A. B[x] implies:  Q
Definitions unfolded in proof :  all: x:A. B[x] uall: [x:A]. B[x] implies:  Q member: t ∈ T so_lambda: λ2x.t[x] so_apply: x[s] prop: label: ...$L... t rfun: I ⟶ℝ rfun-eq: rfun-eq(I;f;g) r-ap: f(x)
Lemmas referenced :  derivative_functionality_wrt_subinterval derivative_wf i-member_wf real_wf subinterval_wf rfun-eq_wf rfun_wf interval_wf set_wf derivative_functionality
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity lambdaFormation isect_memberFormation cut introduction extract_by_obid sqequalHypSubstitution dependent_functionElimination thin because_Cache hypothesisEquality isectElimination sqequalRule independent_functionElimination hypothesis lambdaEquality applyEquality setElimination rename dependent_set_memberEquality setEquality

Latex:
\mforall{}I,J:Interval.
    \mforall{}[f1,f2,g1,g2:I  {}\mrightarrow{}\mBbbR{}].
        (rfun-eq(I;f1;f2)
        {}\mRightarrow{}  rfun-eq(I;g1;g2)
        {}\mRightarrow{}  J  \msubseteq{}  I 
        {}\mRightarrow{}  d(f1[x])/dx  =  \mlambda{}x.g1[x]  on  I
        {}\mRightarrow{}  d(f2[x])/dx  =  \mlambda{}x.g2[x]  on  J)



Date html generated: 2018_05_22-PM-02_44_18
Last ObjectModification: 2017_10_20-PM-00_15_48

Theory : reals


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