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Step * 1 of Lemma real-has-valueall

.....antecedent..... 
1. x : ℕ+ ⟶ ℤ
2. regular-seq(x)
⊢ ↓∃a:ℕ+. value-type(ℤ)
BY
{ (D 0 THEN With ⌜1⌝ (D 0)⋅ THEN Auto) }

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Latex:

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Latex:
.....antecedent..... 
1.  x  :  \mBbbN{}\msupplus{}  {}\mrightarrow{}  \mBbbZ{}
2.  regular-seq(x)
\mvdash{}  \mdownarrow{}\mexists{}a:\mBbbN{}\msupplus{}.  value-type(\mBbbZ{})


By

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Latex:
(D  0  THEN  With  \mkleeneopen{}1\mkleeneclose{}  (D  0)\mcdot{}  THEN  Auto)

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