Nuprl Lemma : expr_functionality
∀[x,y:ℝ].  expr(x) = expr(y) supposing x = y
Proof
Definitions occuring in Statement : 
expr: expr(x)
, 
req: x = y
, 
real: ℝ
, 
uimplies: b supposing a
, 
uall: ∀[x:A]. B[x]
Definitions unfolded in proof : 
uall: ∀[x:A]. B[x]
, 
member: t ∈ T
, 
uimplies: b supposing a
, 
subtype_rel: A ⊆r B
, 
prop: ℙ
, 
uiff: uiff(P;Q)
, 
and: P ∧ Q
, 
rev_uimplies: rev_uimplies(P;Q)
, 
implies: P 
⇒ Q
Lemmas referenced : 
req_functionality, 
expr_wf, 
real_wf, 
req_wf, 
rexp_wf, 
expr-req, 
req_witness, 
req_weakening, 
rexp_functionality
Rules used in proof : 
sqequalSubstitution, 
sqequalTransitivity, 
computationStep, 
sqequalReflexivity, 
isect_memberFormation, 
introduction, 
cut, 
extract_by_obid, 
sqequalHypSubstitution, 
isectElimination, 
thin, 
hypothesisEquality, 
hypothesis, 
applyEquality, 
lambdaEquality, 
setElimination, 
rename, 
setEquality, 
sqequalRule, 
independent_isectElimination, 
productElimination, 
independent_functionElimination, 
isect_memberEquality, 
because_Cache, 
equalityTransitivity, 
equalitySymmetry
Latex:
\mforall{}[x,y:\mBbbR{}].    expr(x)  =  expr(y)  supposing  x  =  y
Date html generated:
2017_10_04-PM-10_38_03
Last ObjectModification:
2017_06_24-AM-11_02_53
Theory : reals_2
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