Nuprl Lemma : gcd-reduce-ext

∀p,q:ℤ.  ∃g:ℕ. ∃a,b,x,y:ℤ. ((p = (a * g) ∈ ℤ) ∧ (q = (b * g) ∈ ℤ) ∧ (((x * a) + (y * b)) = 1 ∈ ℤ))


Proof




Definitions occuring in Statement :  nat: ℕ,  all: ∀x:A. B[x],  exists: ∃x:A. B[x],  and: P ∧ Q,  multiply: n * m,  add: n + m,  natural_number: $n,  int: ℤ,  equal: s = t ∈ T
Definitions unfolded in proof :  member: t ∈ T,  remainder: n rem m,  divide: n ÷ m,  subtract: n - m,  so_apply: x[s1;s2],  natrec: natrec,  genrec: genrec,  genrec-ap: genrec-ap,  spreadn: spread7,  gcd-reduce,  decidable__equal_int,  decidable__int_equal,  uall: ∀[x:A]. B[x],  so_lambda: so_lambda(x,y,z,w.t[x; y; z; w]),  so_apply: x[s1;s2;s3;s4],  so_lambda: λ2x.t[x],  top: Top,  so_apply: x[s],  uimplies: b supposing a,  strict4: strict4(F),  and: P ∧ Q,  all: ∀x:A. B[x],  implies: P ⇒ Q,  has-value: (a)↓,  prop: ℙ,  or: P ∨ Q,  squash: ↓T,  so_lambda: λ2x y.t[x; y]
Lemmas referenced :  gcd-reduce,  lifting-strict-int_eq,  istype-void,  strict4-decide,  lifting-strict-spread,  has-value_wf_base,  istype-base,  is-exception_wf,  decidable__equal_int,  decidable__int_equal
Rules used in proof :  introduction,  sqequalSubstitution,  sqequalTransitivity,  computationStep,  sqequalReflexivity,  cut,  instantiate,  extract_by_obid,  hypothesis,  sqequalRule,  thin,  sqequalHypSubstitution,  equalityTransitivity,  equalitySymmetry,  isectElimination,  baseClosed,  Error :isect_memberEquality_alt,  voidElimination,  independent_isectElimination,  independent_pairFormation,  Error :lambdaFormation_alt,  callbyvalueCallbyvalue,  callbyvalueReduce,  Error :universeIsType,  baseApply,  closedConclusion,  hypothesisEquality,  callbyvalueExceptionCases,  Error :inrFormation_alt,  imageMemberEquality,  imageElimination,  exceptionSqequal,  Error :inlFormation_alt,  Error :inhabitedIsType,  sqequalSqle,  divergentSqle,  callbyvalueSpread,  productElimination,  sqleReflexivity,  Error :equalityIstype,  dependent_functionElimination,  independent_functionElimination,  spreadExceptionCases,  axiomSqleEquality

Latex:
\mforall{}p,q:\mBbbZ{}.    \mexists{}g:\mBbbN{}.  \mexists{}a,b,x,y:\mBbbZ{}.  ((p  =  (a  *  g))  \mwedge{}  (q  =  (b  *  g))  \mwedge{}  (((x  *  a)  +  (y  *  b))  =  1))



Date html generated: 2019_06_20-PM-02_27_15
Last ObjectModification: 2019_03_10-PM-02_40_50

Theory : num_thy_1


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