Step
*
1
1
of Lemma
divisor-test_wf
.....equality.....
1. d : ℕ
2. ∀d:ℕd. ∀n:ℕ. ∀i:ℕ+. ∀j:ℤ.
(((j - i) ≤ d)
⇒ j < n
⇒ (i ≤ j)
⇒ (divisor-test(n;i;j) ∈ {n1:ℤ| n1 < n ∧ (2 ≤ n1) ∧ (n1 | n)} ∨ (gcd(n;iseg_pr\000Coduct(i;j)) = 1 ∈ ℤ)))
3. n : ℕ
4. i : ℕ+
5. j : ℤ
6. (j - i) ≤ d
7. j < n
8. i ≤ j
⊢ better-gcd(n;iseg_product_rem(i;j;n)) = better-gcd(n;iseg_product(i;j)) ∈ ℤ
BY
{ xxx(RWO "better-gcd-gcd" 0 THENA Auto)xxx }
1
1. d : ℕ
2. ∀d:ℕd. ∀n:ℕ. ∀i:ℕ+. ∀j:ℤ.
(((j - i) ≤ d)
⇒ j < n
⇒ (i ≤ j)
⇒ (divisor-test(n;i;j) ∈ {n1:ℤ| n1 < n ∧ (2 ≤ n1) ∧ (n1 | n)} ∨ (gcd(n;iseg_pr\000Coduct(i;j)) = 1 ∈ ℤ)))
3. n : ℕ
4. i : ℕ+
5. j : ℤ
6. (j - i) ≤ d
7. j < n
8. i ≤ j
⊢ gcd(n;iseg_product_rem(i;j;n)) = gcd(n;iseg_product(i;j)) ∈ ℤ
Latex:
Latex:
.....equality.....
1. d : \mBbbN{}
2. \mforall{}d:\mBbbN{}d. \mforall{}n:\mBbbN{}. \mforall{}i:\mBbbN{}\msupplus{}. \mforall{}j:\mBbbZ{}.
(((j - i) \mleq{} d)
{}\mRightarrow{} j < n
{}\mRightarrow{} (i \mleq{} j)
{}\mRightarrow{} (divisor-test(n;i;j) \mmember{} \{n1:\mBbbZ{}| n1 < n \mwedge{} (2 \mleq{} n1) \mwedge{} (n1 | n)\} \mvee{} (gcd(n;iseg\_product(i;j)) = 1\000C)))
3. n : \mBbbN{}
4. i : \mBbbN{}\msupplus{}
5. j : \mBbbZ{}
6. (j - i) \mleq{} d
7. j < n
8. i \mleq{} j
\mvdash{} better-gcd(n;iseg\_product\_rem(i;j;n)) = better-gcd(n;iseg\_product(i;j))
By
Latex:
xxx(RWO "better-gcd-gcd" 0 THENA Auto)xxx
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