Step
*
1
2
of Lemma
qless-minus
1. a : ℚ
2. b : ℚ
3. 0 < -(a) + b ∨ (a = b ∈ ℚ)
4. ¬(0 < a + -(b) ∨ (b = a ∈ ℚ))
⊢ ¬(0 < a + -(b) ∨ (-(a) = -(b) ∈ ℚ))
BY
{ TACTIC:RepeatFor 2 (ParallelLast) }
1
1. a : ℚ
2. b : ℚ
3. 0 < -(a) + b ∨ (a = b ∈ ℚ)
4. -(a) = -(b) ∈ ℚ
⊢ b = a ∈ ℚ
Latex:
Latex:
1. a : \mBbbQ{}
2. b : \mBbbQ{}
3. 0 < -(a) + b \mvee{} (a = b)
4. \mneg{}(0 < a + -(b) \mvee{} (b = a))
\mvdash{} \mneg{}(0 < a + -(b) \mvee{} (-(a) = -(b)))
By
Latex:
TACTIC:RepeatFor 2 (ParallelLast)
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