(
i:
. InvFuns(A;A;f{
i};g{i}))x:A, f:(A
A), i,j,k:. k = i+j f{i}(f{j}(x)) = f{k}(x)f:(AA). f{1} = f InvFuns(B;A;g;f)| Rank | Theorem | Name |
| 2 | (i:. InvFuns(A;A;f{i};g{i})) | [compose_iter_inverses] |
| cites the following: | ||
| 1 | x:A, f:(AA), i,j,k:. k = i+j f{i}(f{j}(x)) = f{k}(x) | [compose_iter_sum] |
| 0 | f:(AA). f{1} = f | [compose_iter_once] |
| 0 | InvFuns(B;A;g;f) | [inv_funs_2_sym] |