Nuprl - Proof: bijtype exteq inj isect surjtype 1 1

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At: bijtype exteq inj isect surjtype 1 1

1. A : Type
2. B : Type
3. x : A bij

(A inj

(A onto

By:	Def THEN Analyze THEN SplitITE Concl THEN BackThru: Thm* (A bij B) (A inj B) \| Thm* (A bij B) (A onto B)

Generated subgoals:

None

About:

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