Nuprl - Proof: nsub inj exteq nsub surj 1 1 1 1 1 1 1 1 1

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At: nsub inj exteq nsub surj 1 1 1 1 1 1 1 1 1

1. k :

2. f :

k inj

k
3. f

k
4. Inj(

k; f)
5. b :

k
6.

(

k. f(a) = b)

k inj

{y:

y = b }

By:	f k{y:k\| y = b } Asserted THEN Analyze

Generated subgoals:

1   f  k{y:k| y = b }
4 steps

2 7. f  k{y:k| y = b }
  Inj(k; {y:k| y = b }; f)
2 steps

About:

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1	f k{y:k\| y = b }	4 steps
2	7. f k{y:k\| y = b } Inj(k; {y:k\| y = b }; f)	2 steps