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At: phole lemma 1

1. n: {1...}
2. m: {n+1...}
3. f: mn

i,j:m. i < j & f(i) = f(j)

By: Inst Thm* n:{1...}, f:((n+1)n). i:(n+1), j:i. f(i) = f(j) [n;f]

Generated subgoal:

14. i:(n+1), j:i. f(i) = f(j)
i,j:m. i < j & f(i) = f(j)


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existsnatural_numberandless_thanequalapplyaddfunction