n
m
0
1of(z)
m+2of(z)nm 1of(z)m+2of(z) < nm Bij(nm; (nm); 
z.1of(z)m+2of(z))
f:(nm
(nm)). Bij(nm; (nm); f)z.1of(z)m+2of(z)| 1 | 3. z: nm 01of(z)m+2of(z) |
| 2 | 3. z: nm 1of(z)m+2of(z) < nm |
| 3 | Bij(nm; (nm); z.1of(z)m+2of(z)) |
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