Nuprl - Proof: bij imp exists inv

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At: bij imp exists inv

A,B:Type, f:(A

B). Bij(A; B; f)

(

g:(B

A). InvFuns(A; B; f; g))

By:

UnivCD

Generated subgoal:

1 1. A : Type
2. B : Type
3. f : AB
4. Bij(A; B; f)
g:(BA). InvFuns(A; B; f; g)
11 steps

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html