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At: mapfilter append

T:Type, P:(T), T':Type, f:({x:T| P(x) }T'), L1,L2:T List. mapfilter(f;P;L1 @ L2) = (mapfilter(f;P;L1) @ mapfilter(f;P;L2))

By:
InductionOnList
THEN
Reduce 0
THEN
Unfold `mapfilter` 0
THEN
Reduce 0
THEN
Repeat SplitOnConclITE
THEN
Reduce 0
THEN
Fold `mapfilter` 0
THEN
Obvious


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About:
listboolassertsetapplyfunctionuniverseequalall

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