Nuprl - Proof: less suc imp

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At: less suc imp

m,n:

. m<n+1

m = n

m<n

By:	RewriteOfThm Thm* all Thm* (m:hnum. all Thm* (m:hnum. (n:hnum. implies Thm* (m:hnum. (n:hnum. (lt(m,suc(n)) Thm* (m:hnum. (n:hnum. ,implies(not(equal(m,n)),lt(m,n))))) (SimpsetC [`hol_to_nuprl`;`bequal`])

Generated subgoals:

None

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html