Nuprl - Proof: decidable all int seg 1

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At: decidable all int seg 1

1. i :

2. j :

3. F : {i..j

}

Prop
4.

k:{i..j

}. Dec(F(k))

Dec(

k:{i..j

}. F(k))

By:	Inst: Thm* i,j:, F:({i..j}Prop). (k:{i..j}. Dec(F(k))) Dec(k:{i..j}. F(k)) Using:[i \| j \| F(k):= F(k)]

Generated subgoal:

1 5. Dec(k:{i..j}. F(k))
Dec(k:{i..j}. F(k))
3 steps

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