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At: not disjoint is member lemma 1 1

1. T: Type
2. eq: {T=}
3. eq TT
4. x,y:T. eq(x,y) x = y
5. L: T List
6. M: T List
7. disjoint(eq;L;M)

x:T. x(eq) L & x(eq) M

By: OnHyps [-1;-1] MoveToConcl

Generated subgoal:

1 M:T List. disjoint(eq;L;M) (x:T. x(eq) L & x(eq) M)

About:
listboolassertapplyfunctionuniverseequal
memberimpliesandallexists

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