Nuprl - Proof: inl eq inr 1

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At: inl eq inr 1

1. A : Type
2. B : Type
3. x : A
4. y : B
5. inl(x) = inr(y)

False

By:	ApFunToHypEquands `Z' InjCase(Z; a. 0; b. 1) -1 THEN Reduce -1

Generated subgoals:

None

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