Nuprl - Proof: cons sublist cons 2 2 2

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At: cons sublist cons 2 2 2

1. T : Type
2. x1 : T
3. x2 : T
4. L1 : T List
5. L2 : T List
6. f :

(||L1||+1)

||L2||
7. increasing(f;||L1||+1)
8.

(||L1||+1). [x1 / L1][j] = L2[(f(j))]
9. j :

(||L1||+1)

[x1 / L1][j] = [x2 / L2][((

j.f(j)+1)(j))]

By:

Reduce 0

Generated subgoal:

1 [x1 / L1][j] = [x2 / L2][(f(j)+1)]
5 steps

About:

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