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At: cons sublist cons 2 2

1. T : Type
2. x1 : T
3. x2 : T
4. L1 : T List
5. L2 : T List
6. f : (||L1||+1)||L2||
7. increasing(f;||L1||+1)
8. j:(||L1||+1). [x1 / L1][j] = L2[(f(j))]
  f:((||L1||+1)(||L2||+1)). 
  increasing(f;||L1||+1) & (j:(||L1||+1). [x1 / L1][j] = [x2 / L2][(f(j))])


By: InstConcl [j.f(j)+1]


Generated subgoals:

1   increasing(j.f(j)+1;||L1||+1)
1 step
2 9. j : (||L1||+1)
  [x1 / L1][j] = [x2 / L2][((j.f(j)+1)(j))]

6 steps

About:
listconsnatural_numberaddlambdaapply
functionuniverseequalandall
exists
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