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At: last cons

  T:Type, L:T List, x:Tnull(L last([x / L]) = last(L)

By: Unfold `last` 0 THEN Reduce 0 THEN Assert (||L||>0)
THENL
[RW assert_pushdownC -1 THEN Easy
;RWO Thm* a:Tas:T List, i:. 0<i  i||as||  [a / as][i] = as[(i-1)] 0]


Generated subgoals:

None

About:
listconsassertintnatural_numbersubtractless_thanuniverseequalimpliesall
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