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At: sum switch 1 2 2 1 2 1

1. n : 
2. f : n
3. i : (n-1)
4. (ii+1)  nn
  sum(f((ii+1)(x+i)) | x < 2) = sum(f(x+i) | x < 2)


By: Unfold `sum` 0 THEN RecUnfold `primrec` 0 THEN Reduce 0 THEN Unfold `flip` 0
THEN
Reduce 0
THEN
Repeat SplitOnConclITE


Generated subgoals:

None

About:
intnatural_numberaddsubtractapplyfunctionequalmember
IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html

(16steps total) PrintForm Definitions Lemmas mb nat Sections MarkB generic Doc