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At: sum switch 1 2 2 2

1. n : 
2. f : n
3. i : (n-1)
4. (ii+1)  nn
  sum(f(x) | x < i)+sum(f(x+i) | x < n-i) = sum(f(x) | x < n)


By: RWO "sum_split<" 0


Generated subgoals:

None

About:
intnatural_numberaddsubtractfunctionequalmember
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(16steps total) PrintForm Definitions Lemmas mb nat Sections MarkB generic Doc