Nuprl - Proof: quot rem exists n 1 1 1 2 1

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At: quot rem exists n 1 1 1 2 1

1. a :

2. b :

3. c :

c1:

. c1<c

(

. a = q

b+c1)

(

, r:

b. a = q

b+r)
5.

. a = q

b+c
6.

c<b

. a = q

b+c-b

By:	Analyze 5 THEN InstConcl [q+1]

Generated subgoals:

None

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html