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Step * of Lemma bpa-minus_wf

∀[p:ℕ+]. ∀[x:basic-padic(p)].  (bpa-minus(p;x) ∈ basic-padic(p))
BY
{ ProveWfLemma }

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Latex:

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Latex:
\mforall{}[p:\mBbbN{}\msupplus{}].  \mforall{}[x:basic-padic(p)].    (bpa-minus(p;x)  \mmember{}  basic-padic(p))


By

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Latex:
ProveWfLemma

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