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Step * of Lemma p-sep_wf

∀[p:ℕ+]. ∀[x,y:p-adics(p)].  (p-sep(x;y) ∈ ℙ)
BY
{ ProveWfLemma }

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Latex:

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Latex:
\mforall{}[p:\mBbbN{}\msupplus{}].  \mforall{}[x,y:p-adics(p)].    (p-sep(x;y)  \mmember{}  \mBbbP{})


By

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Latex:
ProveWfLemma

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