Nuprl Lemma : subtype-fpf-void
∀[A:Type]. ∀[B1:Top]. ∀[B2:A ─→ Type]. (a:Void fp-> B1[a] ⊆r a:A fp-> B2[a])
Proof
Definitions occuring in Statement :
fpf: a:A fp-> B[a],
subtype_rel: A ⊆r B,
uall: ∀[x:A]. B[x],
top: Top,
so_apply: x[s],
function: x:A ─→ B[x],
void: Void,
universe: Type
Lemmas :
subtype-fpf3,
void_wf,
strong-subtype-void,
top_wf
\mforall{}[A:Type]. \mforall{}[B1:Top]. \mforall{}[B2:A {}\mrightarrow{} Type]. (a:Void fp-> B1[a] \msubseteq{}r a:A fp-> B2[a])
Date html generated:
2015_07_17-AM-09_15_32
Last ObjectModification:
2015_01_28-AM-07_52_45
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