Step
*
of Lemma
subtype-fpf-void
∀[A:Type]. ∀[B1:Top]. ∀[B2:A ─→ Type]. (a:Void fp-> B1[a] ⊆r a:A fp-> B2[a])
BY
{ Auto }
Latex:
\mforall{}[A:Type]. \mforall{}[B1:Top]. \mforall{}[B2:A {}\mrightarrow{} Type]. (a:Void fp-> B1[a] \msubseteq{}r a:A fp-> B2[a])
By
Auto
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