Nuprl Lemma : es-first-since_wf
∀[es:EO]. ∀[e1:E]. ∀[e2:{e:E| loc(e) = loc(e1) ∈ Id} ]. ∀[p:{e:E| loc(e) = loc(e1) ∈ Id} ─→ ℙ].
(e2 = first e ≥ e1.p[e] ∈ ℙ)
Proof
Definitions occuring in Statement :
es-first-since: e2 = first e ≥ e1.P[e],
es-loc: loc(e),
es-E: E,
event_ordering: EO,
Id: Id,
uall: ∀[x:A]. B[x],
prop: ℙ,
so_apply: x[s],
member: t ∈ T,
set: {x:A| B[x]} ,
function: x:A ─→ B[x],
equal: s = t ∈ T
Lemmas :
es-le_wf,
alle-between1_wf,
Id_wf,
es-loc_wf,
not_wf,
es-E_wf,
set_wf,
event_ordering_wf
\mforall{}[es:EO]. \mforall{}[e1:E]. \mforall{}[e2:\{e:E| loc(e) = loc(e1)\} ]. \mforall{}[p:\{e:E| loc(e) = loc(e1)\} {}\mrightarrow{} \mBbbP{}].
(e2 = first e \mgeq{} e1.p[e] \mmember{} \mBbbP{})
Date html generated:
2015_07_17-AM-08_52_52
Last ObjectModification:
2015_01_27-PM-01_17_27
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