Nuprl Lemma : listify-append-last

[T:Type]. [m:]. [n:{n:| n  m } ]. [f:{m..n + 1}  T].  (listify(f;m;n + 1) = (listify(f;m;n) @ [f n]))


Proof not projected




Definitions occuring in Statement :  listify: listify(f;m;n) append: as @ bs int_seg: {i..j} uall: [x:A]. B[x] ge: i  j  set: {x:A| B[x]}  apply: f a function: x:A  B[x] cons: [car / cdr] nil: [] list: type List add: n + m natural_number: $n int: universe: Type equal: s = t
Definitions :  ge: i  j  int_seg: {i..j} listify: listify(f;m;n) and: P  Q le: A  B member: t  T not: A implies: P  Q false: False prop: rev_implies: P  Q iff: P  Q all: x:A. B[x] subtype: S  T suptype: suptype(S; T) lelt: i  j < k ycomb: Y ifthenelse: if b then t else f fi  btrue: tt bfalse: ff uall: [x:A]. B[x] bool: unit: Unit uimplies: b supposing a uiff: uiff(P;Q) guard: {T} it:
Lemmas :  listify-append le_wf append_wf listify_wf int_seg_wf le_int_wf bool_wf assert_wf lt_int_wf bnot_wf ge_wf uiff_transitivity eqtt_to_assert assert_of_le_int eqff_to_assert assert_functionality_wrt_uiff bnot_of_le_int assert_of_lt_int

\mforall{}[T:Type].  \mforall{}[m:\mBbbZ{}].  \mforall{}[n:\{n:\mBbbZ{}|  n  \mgeq{}  m  \}  ].  \mforall{}[f:\{m..n  +  1\msupminus{}\}  {}\mrightarrow{}  T].
    (listify(f;m;n  +  1)  =  (listify(f;m;n)  @  [f  n]))


Date html generated: 2012_02_20-PM-05_59_09
Last ObjectModification: 2012_02_02-PM-02_30_38

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