{ 
[es:EO]. [e1,e2:E]. [P:{e:E| (loc(e) = loc(e1)) 
(
first(e))} 
].
e
(e1,e2].P[e] supposing loc(e2) = loc(e1) }
{ Proof }
Definitions occuring in Statement :
alle-between3: e(e1,e2].P[e],
es-first: first(e),
es-loc: loc(e),
es-E: E,
event_ordering: EO,
Id: Id,
assert: b,
uimplies: b supposing a,
uall: [x:A]. B[x],
prop: ,
so_apply: x[s],
not: A,
and: P Q,
member: t T,
set: {x:A| B[x]} ,
function: x:A B[x],
equal: s = t
Definitions :
uall: [x:A]. B[x],
and: P Q,
not: A,
assert: b,
prop: ,
uimplies: b supposing a,
member: t T,
alle-between3: e(e1,e2].P[e],
so_apply: x[s],
all: x:A. B[x],
implies: P 
Q,
false: False,
bfalse: ff,
ifthenelse: if b then t else f fi ,
es-locl: (e <loc e'),
sq_type: SQType(T),
guard: {T}
Lemmas :
es-E_wf,
es-locl_wf,
es-le_wf,
subtype_base_sq,
bool_wf,
bool_subtype_base,
false_wf,
assert_wf,
es-first_wf,
Id_wf,
es-loc_wf,
not_wf,
event_ordering_wf,
es-locl-first
\mforall{}[es:EO]. \mforall{}[e1,e2:E]. \mforall{}[P:\{e:E| (loc(e) = loc(e1)) \mwedge{} (\mneg{}\muparrow{}first(e))\} {}\mrightarrow{} \mBbbP{}].
\mforall{}e\mmember{}(e1,e2].P[e] \mmember{} \mBbbP{} supposing loc(e2) = loc(e1)
Date html generated:
2011_08_16-AM-10_48_51
Last ObjectModification:
2011_06_18-AM-09_23_22
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