Step * of Lemma sqntype_list

[A:Type]. ∀[n:ℕ].  sqntype(n;A List) supposing sqntype(n;A)
BY
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1
1. Type
2. : ℕ
3. sqntype(n;A)
⊢ sqntype(n;A List)


Latex:


Latex:
\mforall{}[A:Type].  \mforall{}[n:\mBbbN{}].    sqntype(n;A  List)  supposing  sqntype(n;A)


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Latex:
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