Nuprl Lemma : sqle_trans

a,b,c:Base.  ((a ≤ b)  (b ≤ c)  (a ≤ c))


Proof




Definitions occuring in Statement :  all: x:A. B[x] implies:  Q base: Base sqle: s ≤ t
Definitions unfolded in proof :  all: x:A. B[x] implies:  Q uall: [x:A]. B[x] member: t ∈ T
Lemmas referenced :  sqle-wf base_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity Error :lambdaFormation_alt,  sqleTransitivity hypothesis Error :universeIsType,  cut introduction extract_by_obid sqequalHypSubstitution isectElimination thin hypothesisEquality Error :inhabitedIsType

Latex:
\mforall{}a,b,c:Base.    ((a  \mleq{}  b)  {}\mRightarrow{}  (b  \mleq{}  c)  {}\mRightarrow{}  (a  \mleq{}  c))



Date html generated: 2019_06_20-AM-11_19_42
Last ObjectModification: 2018_10_06-AM-09_22_18

Theory : sqequal_1


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