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Step * of Lemma inr-one-one'

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∀[A,B:Type]. ∀[x,y:B].  x = y ∈ B supposing (inr x ) = (inr y ) ∈ (A + B)
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\mforall{}[A,B:Type].  \mforall{}[x,y:B].    x  =  y  supposing  (inr  x  )  =  (inr  y  )


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