---

Step * of Lemma bag-filter-union2

∀[T:Type]. ∀[p:T ⟶ 𝔹]. ∀[bbs:bag(bag(T))].  ([x∈bag-union(bbs)|p[x]] = bag-union(bag-map(λb.[x∈b|p[x]];bbs)) ∈ bag(T))
BY
{ ((Auto THEN D -1) THENA Auto) }

---

Latex:

---

Latex:
\mforall{}[T:Type].  \mforall{}[p:T  {}\mrightarrow{}  \mBbbB{}].  \mforall{}[bbs:bag(bag(T))].
    ([x\mmember{}bag-union(bbs)|p[x]]  =  bag-union(bag-map(\mlambda{}b.[x\mmember{}b|p[x]];bbs)))


By

---

Latex:
((Auto  THEN  D  -1)  THENA  Auto)

---

Home Index