Nuprl Lemma : null-bag-mapfilter

P,f,bs:Top.  (bag-null(bag-mapfilter(f;P;bs)) bag-null([x∈bs|P x]))


Proof




Definitions occuring in Statement :  bag-null: bag-null(bs) bag-mapfilter: bag-mapfilter(f;P;bs) bag-filter: [x∈b|p[x]] top: Top all: x:A. B[x] apply: a sqequal: t
Definitions unfolded in proof :  bag-null: bag-null(bs)
Lemmas referenced :  bag-mapfilter-null
Rules used in proof :  sqequalSubstitution sqequalRule sqequalReflexivity sqequalTransitivity computationStep cut lemma_by_obid hypothesis

Latex:
\mforall{}P,f,bs:Top.    (bag-null(bag-mapfilter(f;P;bs))  \msim{}  bag-null([x\mmember{}bs|P  x]))



Date html generated: 2016_05_15-PM-02_24_25
Last ObjectModification: 2015_12_27-AM-09_53_29

Theory : bags


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