Nuprl Lemma : bag-mapfilter-null

P,f,bs:Top.  (null(bag-mapfilter(f;P;bs)) null([x∈bs|P x]))


Proof




Definitions occuring in Statement :  bag-mapfilter: bag-mapfilter(f;P;bs) bag-filter: [x∈b|p[x]] null: null(as) top: Top all: x:A. B[x] apply: a sqequal: t
Definitions unfolded in proof :  bag-mapfilter: bag-mapfilter(f;P;bs) all: x:A. B[x] member: t ∈ T top: Top
Lemmas referenced :  bag-map-null top_wf
Rules used in proof :  sqequalSubstitution sqequalRule sqequalReflexivity sqequalTransitivity computationStep lambdaFormation cut lemma_by_obid sqequalHypSubstitution dependent_functionElimination thin hypothesisEquality isect_memberEquality voidElimination voidEquality hypothesis

Latex:
\mforall{}P,f,bs:Top.    (null(bag-mapfilter(f;P;bs))  \msim{}  null([x\mmember{}bs|P  x]))



Date html generated: 2016_05_15-PM-02_23_49
Last ObjectModification: 2015_12_27-AM-09_53_51

Theory : bags


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