Step
*
of Lemma
fpf-join-is-empty
No Annotations
∀[A:Type]. ∀[eq:EqDecider(A)]. ∀[f,g:x:A fp-> Top]. (fpf-is-empty(f ⊕ g) ~ fpf-is-empty(f) ∧b fpf-is-empty(g))
BY
{ TACTIC:(Auto
THEN (D (-2))
THEN (D (-1))
THEN Repeat ((Unfolds ``fpf-is-empty fpf-join fpf-dom`` 0 THEN Reduce 0))
THEN All Thin) }
1
1. A : Type
2. eq : EqDecider(A)
3. d : A List
4. d1 : A List
⊢ (||d @ filter(λa.(¬ba ∈b d);d1)|| =z 0) = (||d|| =z 0) ∧b (||d1|| =z 0)
Latex:
Latex:
No Annotations
\mforall{}[A:Type]. \mforall{}[eq:EqDecider(A)]. \mforall{}[f,g:x:A fp-> Top].
(fpf-is-empty(f \moplus{} g) \msim{} fpf-is-empty(f) \mwedge{}\msubb{} fpf-is-empty(g))
By
Latex:
TACTIC:(Auto
THEN (D (-2))
THEN (D (-1))
THEN Repeat ((Unfolds ``fpf-is-empty fpf-join fpf-dom`` 0 THEN Reduce 0))
THEN All Thin)
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