Step
*
1
2
of Lemma
int-to-ring-add
1. r : Rng
2. a1 : ℤ
3. a2 : ℤ
4. ∀x:ℤ. (int-to-ring(r;x + 1) = (int-to-ring(r;x) +r 1) ∈ |r|)
⊢ int-to-ring(r;a1 + a2) = (int-to-ring(r;a1) +r int-to-ring(r;a2)) ∈ |r|
BY
{ xxxAssert ⌜∀x:ℤ. (int-to-ring(r;x - 1) = (int-to-ring(r;x) +r (-r 1)) ∈ |r|)⌝⋅xxx }
1
.....assertion.....
1. r : Rng
2. a1 : ℤ
3. a2 : ℤ
4. ∀x:ℤ. (int-to-ring(r;x + 1) = (int-to-ring(r;x) +r 1) ∈ |r|)
⊢ ∀x:ℤ. (int-to-ring(r;x - 1) = (int-to-ring(r;x) +r (-r 1)) ∈ |r|)
2
1. r : Rng
2. a1 : ℤ
3. a2 : ℤ
4. ∀x:ℤ. (int-to-ring(r;x + 1) = (int-to-ring(r;x) +r 1) ∈ |r|)
5. ∀x:ℤ. (int-to-ring(r;x - 1) = (int-to-ring(r;x) +r (-r 1)) ∈ |r|)
⊢ int-to-ring(r;a1 + a2) = (int-to-ring(r;a1) +r int-to-ring(r;a2)) ∈ |r|
Latex:
Latex:
1. r : Rng
2. a1 : \mBbbZ{}
3. a2 : \mBbbZ{}
4. \mforall{}x:\mBbbZ{}. (int-to-ring(r;x + 1) = (int-to-ring(r;x) +r 1))
\mvdash{} int-to-ring(r;a1 + a2) = (int-to-ring(r;a1) +r int-to-ring(r;a2))
By
Latex:
xxxAssert \mkleeneopen{}\mforall{}x:\mBbbZ{}. (int-to-ring(r;x - 1) = (int-to-ring(r;x) +r (-r 1)))\mkleeneclose{}\mcdot{}xxx
Home
Index