Nuprl - Proof: compose iter inj cycles 1 1

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At: compose iter inj cycles 1 1

1. k :

2. f :

k
3. Inj(

k; f)
4. u :

. f{

i}(u) = u

By:	i,j:. i<j & f{j}(u) = f{i}(u) k Asserted

Generated subgoals:

1 i,j:. i<j & f{j}(u) = f{i}(u)
6 steps

2 5. i,j:. i<j & f{j}(u) = f{i}(u)
i:. f{i}(u) = u
4 steps

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html

1	i,j:. i<j & f{j}(u) = f{i}(u)	6 steps
2	5. i,j:. i<j & f{j}(u) = f{i}(u) i:. f{i}(u) = u	4 steps