Nuprl - Proof: fun with inv2 is bij

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At: fun with inv2 is bij

A,B:Type, f:(A

B), g:(B

A). InvFuns(A;B;f;g)

Bij(A; B; f)

By:

Auto

Generated subgoal:

1 1. A : Type
2. B : Type
3. f : AB
4. g : BA
5. InvFuns(A;B;f;g)
Bij(A; B; f)
3 steps

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html