Nuprl - Proof: nsub inj discr range bij 1 2 1

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At: nsub inj discr range bij 1 2 1

1. A : Type
2. A Discrete
3. k :

4. f :

A
5. Inj(

k; A; f)
6. {a:A|

k. a = f(i) }

Type
7. f

{a:A|

k. a = f(i) } & Surj(

k; {a:A|

k. a = f(i) }; f)
8. {a:A|

k. a = f(i) }

Type

{a:A|

k. a = f(i) } & Bij(

k; {a:A|

k. a = f(i) }; f)

By:	Def of Bij(<A>; <B>; <f>) THEN SimilarTo: Hyp:7

Generated subgoal:

1 9. f  k{a:A| i:k. a = f(i) }
10. Surj(k; {a:A| i:k. a = f(i) }; f)
11. f  k{a:A| i:k. a = f(i) }
  Inj(k; {a:A| i:k. a = f(i) }; f)
1 step

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