Nuprl - Proof: nsub inj discr range bijtype 1

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At: nsub inj discr range bijtype 1

1. A : Type
2. A Discrete
3. k :

4. f :

k inj

A
5. {a:A|

k. a = f(i) }

Type
6. f

{a:A|

k. a = f(i) }
7. Bij(

k; {a:A|

k. a = f(i) }; f)

k bij

{a:A|

k. a = f(i) }

By:

Analyze

Generated subgoals:

None

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IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html