Nuprl - Proof: nsub inj exteq nsub surj 1 1 1 1 1 1 1 1 1 2 1

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At: nsub inj exteq nsub surj 1 1 1 1 1 1 1 1 1 2 1

1. k :

2. f :

k inj

k
3. f

k
4. Inj(

k; f)
5. b :

k
6.

(

k. f(a) = b)
7. f

{y:

y = b }
8. a1 :

k
9. a2 :

k
10. f(a1) = f(a2)

a1 = a2

By:	Analyze-1 THEN BackThru: Hyp:4

Generated subgoals:

None

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html