At:
append upto
1
3
1.
d:
2.
0 < d
3.
i,j,k:
. j-i = d-1 
j
k 
(upto(i;k) ~ (upto(i;j) @ upto(j;k)))
4.
i:
5.
j:
6.
k:
7.
j-i = d
8.
j
k
9.
i < k
10.
i < j
[i / upto(i+1;k)] ~ [i / (upto(i+1;j) @ upto(j;k))]
By:
Analyze
THEN
EasyHyp
Generated subgoals:
None
About: