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At: rep prod axiom

  'a,'b:S.
  (p:'a'ba:'ab:'b. (a = 1of(p))(b = 2of(p)))
  =
  (@rep:'a'b'a'b
  (@((p',p'':'a'b.  ((rep(p')) = (rep(p'')))(p' = p''))
  (@(x:'a'b
  (@(((his_pair('a'b)(x)) = (p':'a'b. (x = (rep(p'))))))))


By: UseWitness * THEN Fiat


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productboolapplyfunctionequalaxiomall
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