Nuprl - Proof: exp add

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html
At: exp add

x,q,n:

. exp(n;x+q) = exp(n;x)

exp(n;q)

By:	RewriteOfThm Thm* all Thm* (p:hnum. all Thm* (p:hnum. (q:hnum. all Thm* (p:hnum. (q:hnum. (n:hnum. equal Thm* (p:hnum. (q:hnum. (n:hnum. (exp(n,add(p,q)) Thm* (p:hnum. (q:hnum. (n:hnum. ,mult(exp(n,p),exp(n,q)))))) (SimpsetC [`hol_to_nuprl`;`bequal`])

Generated subgoals:

None

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html