Nuprl - Proof: sub right sub

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html
At: sub right sub

m,n,x:

. nnsub(nnsub(m;n);x) = nnsub(m;n+x)

By:	RewriteOfThm Thm* all Thm* (m:hnum. all Thm* (m:hnum. (n:hnum. all(p:hnum. equal(sub(sub(m,n),p),sub(m,add(n,p)))))) (SimpsetC [`hol_to_nuprl`;`bequal`])

Generated subgoals:

None

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html