Nuprl - Proof: iter via intseg split pluck 1

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At: iter via intseg split pluck 1

1. A : Type
2. f : A

A
3. u : A
4. is_ident(A; f; u)
5. is_assoc_sep(A; f)
6. a :

7. c :

8. b :

9. e : {a..b

}

A
10. a

c
11. c<b
12. (Iter(f;u) i:{a..b

}. e(i))
12. =
12. f((Iter(f;u) i:{a..c

}. e(i)),Iter(f;u) i:{c..b

}. e(i))

(Iter(f;u) i:{a..b

}. e(i))

f((Iter(f;u) i:{a..c

}. e(i)),f(e(c),Iter(f;u) i:{c+1..b

}. e(i)))

By:	Rewrite by Hyp:-1

Generated subgoal:

1   f((Iter(f;u) i:{a..c}. e(i)),Iter(f;u) i:{c..b}. e(i))
  =
  f((Iter(f;u) i:{a..c}. e(i)),f(e(c),Iter(f;u) i:{c+1..b}. e(i)))
4 steps

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