By: |
(Thm* i:, E:({...i}Prop). (Thm* E(i) (k:{...i-1}. E(k+1) E(k)) (k:{...i}. E(k))) THEN UnivCD |
1 |
5. i : {n..n} (f{n..n})[(i-n)] = f(i) | 1 step |
2 |
5. 0j+1 (i:{(j+1)..n}. (f{(j+1)..n})[(i-(j+1))] = f(i)) 6. 0j 7. i : {j..n} (f{j..n})[(i-j)] = f(i) | 7 steps |
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