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At: not disjoint is member lemma 1 1 1 2 1 1 1 1 1 1 2
1. T: Type
2. eq: {T=}
3. eq TT
4. x,y:T. eq(x,y) x = y
5. L: T List
6. u: T
7. v: T List
8. M:T List. disjoint(eq;v;M) (x:T. x(eq) v & x(eq) M)
9. M: T List
10. u(eq) M
11. eq(u,u) = false

u(eq) v & u(eq) M
By:
Witness4 u
THEN
With u (Analyze -1)
Generated subgoal:

14. L: T List
5. u: T
6. v: T List
7. M:T List. disjoint(eq;v;M) (x:T. x(eq) v & x(eq) M)
8. M: T List
9. u(eq) M
10. eq(u,u) = false
11. eq(u,u) u = u
u(eq) v & u(eq) M

About:
listboolbfalseassertapplyfunctionuniverseequal
memberimpliesandallexists

(33steps) PrintForm Definitions Lemmas list 3 jlc Sections Support(jlc) Doc